Base | Representation |
---|---|
bin | 100000100010110110000101… |
… | …111001001101001111001011 |
3 | 200202210021210101002020010012 |
4 | 200202312011321031033023 |
5 | 122230033400031132410 |
6 | 1224225540355542135 |
7 | 42101643112600514 |
oct | 4042660571151713 |
9 | 622707711066105 |
10 | 143132031505355 |
11 | 41673a543820a2 |
12 | 14077b438ba94b |
13 | 61b33a5c706a9 |
14 | 274b8ad3c9a0b |
15 | 11832d50cb605 |
hex | 822d85e4d3cb |
143132031505355 has 16 divisors (see below), whose sum is σ = 171784455194880. Its totient is φ = 114488281277568.
The previous prime is 143132031505327. The next prime is 143132031505399. The reversal of 143132031505355 is 553505130231341.
It is a cyclic number.
It is not a de Polignac number, because 143132031505355 - 242 = 138733984994251 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2215188029 + ... + 2215252641.
It is an arithmetic number, because the mean of its divisors is an integer number (10736528449680).
Almost surely, 2143132031505355 is an apocalyptic number.
143132031505355 is a deficient number, since it is larger than the sum of its proper divisors (28652423689525).
143132031505355 is an equidigital number, since it uses as much as digits as its factorization.
143132031505355 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 124870.
The product of its (nonzero) digits is 405000, while the sum is 41.
Adding to 143132031505355 its reverse (553505130231341), we get a palindrome (696637161736696).
The spelling of 143132031505355 in words is "one hundred forty-three trillion, one hundred thirty-two billion, thirty-one million, five hundred five thousand, three hundred fifty-five".
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