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14313301123 = 116172108929
BaseRepresentation
bin11010101010010001…
…11010010010000011
31100221112000000220211
431111020322102003
5213303201113443
610324143414551
71014461023612
oct152510722203
940845000824
1014313301123
116085537a90
1229355b4457
1314714b5c64
1499ad4d879
1558b8bd19d
hex35523a483

14313301123 has 8 divisors (see below), whose sum is σ = 15639824880. Its totient is φ = 12990996480.

The previous prime is 14313301109. The next prime is 14313301127. The reversal of 14313301123 is 32110331341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14313301123 - 25 = 14313301091 is a prime.

It is a super-2 number, since 2×143133011232 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14313301094 and 14313301103.

It is not an unprimeable number, because it can be changed into a prime (14313301127) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1047678 + ... + 1061251.

It is an arithmetic number, because the mean of its divisors is an integer number (1954978110).

Almost surely, 214313301123 is an apocalyptic number.

14313301123 is a deficient number, since it is larger than the sum of its proper divisors (1326523757).

14313301123 is a wasteful number, since it uses less digits than its factorization.

14313301123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2109557.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 14313301123 its reverse (32110331341), we get a palindrome (46423632464).

The spelling of 14313301123 in words is "fourteen billion, three hundred thirteen million, three hundred one thousand, one hundred twenty-three".

Divisors: 1 11 617 6787 2108929 23198219 1301209193 14313301123