14313311433 has 12 divisors (see below), whose sum is σ = 20691352500. Its totient is φ = 9534560256.

The previous prime is 14313311423. The next prime is 14313311443. The reversal of 14313311433 is 33411331341.

14313311433 is a `hidden beast` number, since 1 + 4 + 313 + 311 + 4 + 33 = 666.

14313311433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (14313311423) and next prime (14313311443).

It can be written as a sum of positive squares in 2 ways, for example, as 1959655824 + 12353655609 = 44268^2 + 111147^2 .

It is not a de Polignac number, because 14313311433 - 2⁴ = 14313311417 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14313311397 and 14313311406.

It is not an unprimeable number, because it can be changed into a prime (14313311423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 625416 + ... + 647897.

It is an arithmetic number, because the mean of its divisors is an integer number (1724279375).

Almost surely, 2^14313311433 is an apocalyptic number.

It is an amenable number.

14313311433 is a deficient number, since it is larger than the sum of its proper divisors (6378041067).

14313311433 is a wasteful number, since it uses less digits than its factorization.

14313311433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1274568 (or 1274565 counting only the distinct ones).

The product of its digits is 3888, while the sum is 27.

Adding to 14313311433 its reverse (33411331341), we get a palindrome (47724642774).

The spelling of 14313311433 in words is "fourteen billion, three hundred thirteen million, three hundred eleven thousand, four hundred thirty-three".