14313400201 has 4 divisors (see below), whose sum is σ = 14320605712. Its totient is φ = 14306194692.

The previous prime is 14313400151. The next prime is 14313400229. The reversal of 14313400201 is 10200431341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14313400201 - 2¹¹ = 14313398153 is a prime.

It is a super-3 number, since 3×14313400201³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14313400001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3599775 + ... + 3603748.

It is an arithmetic number, because the mean of its divisors is an integer number (3580151428).

Almost surely, 2^14313400201 is an apocalyptic number.

It is an amenable number.

14313400201 is a deficient number, since it is larger than the sum of its proper divisors (7205511).

14313400201 is an equidigital number, since it uses as much as digits as its factorization.

14313400201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7205510.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 14313400201 its reverse (10200431341), we get a palindrome (24513831542).

The spelling of 14313400201 in words is "fourteen billion, three hundred thirteen million, four hundred thousand, two hundred one".