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143134204402435 = 5223421304920389
BaseRepresentation
bin100000100010111000000111…
…011010001001101100000011
3200202210111101210202211112211
4200202320013122021230003
5122230102322311334220
61224230540140402551
742102051006115441
oct4042700732115403
9622714353684484
10143134204402435
114167496997a904
121407844b546457
1361b36611a28cc
14274ba37c0db91
1511833b0c42b5a
hex822e07689b03

143134204402435 has 16 divisors (see below), whose sum is σ = 172941087755520. Its totient is φ = 113723107908480.

The previous prime is 143134204402369. The next prime is 143134204402499. The reversal of 143134204402435 is 534204402431341.

It is not a de Polignac number, because 143134204402435 - 223 = 143134196013827 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 151990780 + ... + 152929609.

It is an arithmetic number, because the mean of its divisors is an integer number (10808817984720).

Almost surely, 2143134204402435 is an apocalyptic number.

143134204402435 is a deficient number, since it is larger than the sum of its proper divisors (29806883353085).

143134204402435 is a wasteful number, since it uses less digits than its factorization.

143134204402435 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 304921038.

The product of its (nonzero) digits is 552960, while the sum is 40.

Adding to 143134204402435 its reverse (534204402431341), we get a palindrome (677338606833776).

The spelling of 143134204402435 in words is "one hundred forty-three trillion, one hundred thirty-four billion, two hundred four million, four hundred two thousand, four hundred thirty-five".

Divisors: 1 5 223 421 1115 2105 93883 469415 304920389 1524601945 67997246747 128371483769 339986233735 641857418845 28626840880487 143134204402435