Base | Representation |
---|---|
bin | 100000100010111000000111… |
… | …011010001001101100000011 |
3 | 200202210111101210202211112211 |
4 | 200202320013122021230003 |
5 | 122230102322311334220 |
6 | 1224230540140402551 |
7 | 42102051006115441 |
oct | 4042700732115403 |
9 | 622714353684484 |
10 | 143134204402435 |
11 | 4167496997a904 |
12 | 1407844b546457 |
13 | 61b36611a28cc |
14 | 274ba37c0db91 |
15 | 11833b0c42b5a |
hex | 822e07689b03 |
143134204402435 has 16 divisors (see below), whose sum is σ = 172941087755520. Its totient is φ = 113723107908480.
The previous prime is 143134204402369. The next prime is 143134204402499. The reversal of 143134204402435 is 534204402431341.
It is not a de Polignac number, because 143134204402435 - 223 = 143134196013827 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 151990780 + ... + 152929609.
It is an arithmetic number, because the mean of its divisors is an integer number (10808817984720).
Almost surely, 2143134204402435 is an apocalyptic number.
143134204402435 is a deficient number, since it is larger than the sum of its proper divisors (29806883353085).
143134204402435 is a wasteful number, since it uses less digits than its factorization.
143134204402435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 304921038.
The product of its (nonzero) digits is 552960, while the sum is 40.
Adding to 143134204402435 its reverse (534204402431341), we get a palindrome (677338606833776).
The spelling of 143134204402435 in words is "one hundred forty-three trillion, one hundred thirty-four billion, two hundred four million, four hundred two thousand, four hundred thirty-five".
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