143134226441545 has 4 divisors (see below), whose sum is σ = 171761071729860. Its totient is φ = 114507381153232.

The previous prime is 143134226441539. The next prime is 143134226441579. The reversal of 143134226441545 is 545144622431341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 68593727029689 + 74540499411856 = 8282133^2 + 8633684^2 .

It is a cyclic number.

It is not a de Polignac number, because 143134226441545 - 2¹¹ = 143134226439497 is a prime.

It is a super-3 number, since 3×143134226441545³ (a number of 43 digits) contains 333 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14313422644150 + ... + 14313422644159.

It is an arithmetic number, because the mean of its divisors is an integer number (42940267932465).

Almost surely, 2^{143134226441545} is an apocalyptic number.

It is an amenable number.

143134226441545 is a deficient number, since it is larger than the sum of its proper divisors (28626845288315).

143134226441545 is an equidigital number, since it uses as much as digits as its factorization.

143134226441545 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28626845288314.

The product of its digits is 5529600, while the sum is 49.

Adding to 143134226441545 its reverse (545144622431341), we get a palindrome (688278848872886).

The spelling of 143134226441545 in words is "one hundred forty-three trillion, one hundred thirty-four billion, two hundred twenty-six million, four hundred forty-one thousand, five hundred forty-five".