143135156104051 has 4 divisors (see below), whose sum is σ = 143282566152504. Its totient is φ = 142987746055600.

The previous prime is 143135156104043. The next prime is 143135156104067. The reversal of 143135156104051 is 150401651531341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 143135156104051 - 2³ = 143135156104043 is a prime.

It is a super-2 number, since 2×143135156104051² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 143135156103995 and 143135156104013.

It is not an unprimeable number, because it can be changed into a prime (143135156104751) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73705022770 + ... + 73705024711.

It is an arithmetic number, because the mean of its divisors is an integer number (35820641538126).

Almost surely, 2^{143135156104051} is an apocalyptic number.

143135156104051 is a deficient number, since it is larger than the sum of its proper divisors (147410048453).

143135156104051 is an equidigital number, since it uses as much as digits as its factorization.

143135156104051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 147410048452.

The product of its (nonzero) digits is 108000, while the sum is 40.

The spelling of 143135156104051 in words is "one hundred forty-three trillion, one hundred thirty-five billion, one hundred fifty-six million, one hundred four thousand, fifty-one".