Base | Representation |
---|---|
bin | 11010101010010100… |
… | …01101111000100011 |
3 | 1100221112122102122111 |
4 | 31111022031320203 |
5 | 213303243043210 |
6 | 10324155020151 |
7 | 1014463651141 |
oct | 152512157043 |
9 | 40845572574 |
10 | 14313643555 |
11 | 6085751292 |
12 | 293573a657 |
13 | 14715a5a93 |
14 | 99addc591 |
15 | 58b93988a |
hex | 35528de23 |
14313643555 has 8 divisors (see below), whose sum is σ = 17179344000. Its totient is φ = 11448933696.
The previous prime is 14313643541. The next prime is 14313643607. The reversal of 14313643555 is 55534631341.
14313643555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14313643555 - 27 = 14313643427 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 215475 + ... + 273964.
It is an arithmetic number, because the mean of its divisors is an integer number (2147418000).
Almost surely, 214313643555 is an apocalyptic number.
14313643555 is a deficient number, since it is larger than the sum of its proper divisors (2865700445).
14313643555 is an equidigital number, since it uses as much as digits as its factorization.
14313643555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 495293.
The product of its digits is 324000, while the sum is 40.
The spelling of 14313643555 in words is "fourteen billion, three hundred thirteen million, six hundred forty-three thousand, five hundred fifty-five".
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