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14314022211 = 34771340737
BaseRepresentation
bin11010101010010111…
…01010010101000011
31100221120100200001210
431111023222111003
5213303342202321
610324211101203
71014500116116
oct152513522503
940846320053
1014314022211
11608598a825
1229358a1803
1314716a9238
1499b09a57d
1558b9b1b76
hex3552ea543

14314022211 has 4 divisors (see below), whose sum is σ = 19085362952. Its totient is φ = 9542681472.

The previous prime is 14314022209. The next prime is 14314022221. The reversal of 14314022211 is 11222041341.

14314022211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 14314022211 - 21 = 14314022209 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14314022201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2385670366 + ... + 2385670371.

It is an arithmetic number, because the mean of its divisors is an integer number (4771340738).

Almost surely, 214314022211 is an apocalyptic number.

14314022211 is a deficient number, since it is larger than the sum of its proper divisors (4771340741).

14314022211 is an equidigital number, since it uses as much as digits as its factorization.

14314022211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4771340740.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 14314022211 its reverse (11222041341), we get a palindrome (25536063552).

The spelling of 14314022211 in words is "fourteen billion, three hundred fourteen million, twenty-two thousand, two hundred eleven".

Divisors: 1 3 4771340737 14314022211