Search a number
-
+
1431412053113 = 71911070614849
BaseRepresentation
bin10100110101000110110…
…011101001010001111001
312001211201120022102120102
4110311012303221101321
5141423012441144423
63013325344005145
7205262503461560
oct24650663512171
95054646272512
101431412053113
11502070872769
121b15010007b5
13a4c9b6aa953
144d3d03c2bd7
152737ac0ec28
hex14d46ce9479

1431412053113 has 8 divisors (see below), whose sum is σ = 1644464409600. Its totient is φ = 1220500926720.

The previous prime is 1431412053103. The next prime is 1431412053151. The reversal of 1431412053113 is 3113502141341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1431412053113 - 218 = 1431411790969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1431412053103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 535306088 + ... + 535308761.

It is an arithmetic number, because the mean of its divisors is an integer number (205558051200).

Almost surely, 21431412053113 is an apocalyptic number.

It is an amenable number.

1431412053113 is a deficient number, since it is larger than the sum of its proper divisors (213052356487).

1431412053113 is a wasteful number, since it uses less digits than its factorization.

1431412053113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1070615047.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 1431412053113 its reverse (3113502141341), we get a palindrome (4544914194454).

The spelling of 1431412053113 in words is "one trillion, four hundred thirty-one billion, four hundred twelve million, fifty-three thousand, one hundred thirteen".

Divisors: 1 7 191 1337 1070614849 7494303943 204487436159 1431412053113