Base | Representation |
---|---|
bin | 10100110101000110110… |
… | …011101001010001111001 |
3 | 12001211201120022102120102 |
4 | 110311012303221101321 |
5 | 141423012441144423 |
6 | 3013325344005145 |
7 | 205262503461560 |
oct | 24650663512171 |
9 | 5054646272512 |
10 | 1431412053113 |
11 | 502070872769 |
12 | 1b15010007b5 |
13 | a4c9b6aa953 |
14 | 4d3d03c2bd7 |
15 | 2737ac0ec28 |
hex | 14d46ce9479 |
1431412053113 has 8 divisors (see below), whose sum is σ = 1644464409600. Its totient is φ = 1220500926720.
The previous prime is 1431412053103. The next prime is 1431412053151. The reversal of 1431412053113 is 3113502141341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1431412053113 - 218 = 1431411790969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1431412053103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 535306088 + ... + 535308761.
It is an arithmetic number, because the mean of its divisors is an integer number (205558051200).
Almost surely, 21431412053113 is an apocalyptic number.
It is an amenable number.
1431412053113 is a deficient number, since it is larger than the sum of its proper divisors (213052356487).
1431412053113 is a wasteful number, since it uses less digits than its factorization.
1431412053113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1070615047.
The product of its (nonzero) digits is 4320, while the sum is 29.
Adding to 1431412053113 its reverse (3113502141341), we get a palindrome (4544914194454).
The spelling of 1431412053113 in words is "one trillion, four hundred thirty-one billion, four hundred twelve million, fifty-three thousand, one hundred thirteen".
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