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143142220433 = 1395092023183
BaseRepresentation
bin1000010101001111110…
…0001111001010010001
3111200110211100012211202
42011103330033022101
54321123402023213
6145431510320545
713225124540552
oct2052374171221
9450424305752
10143142220433
1155785062933
12238aa059155
1310662880424
146cdca96329
153acba09b58
hex2153f0f291

143142220433 has 8 divisors (see below), whose sum is σ = 144455337600. Its totient is φ = 141833150928.

The previous prime is 143142220399. The next prime is 143142220447. The reversal of 143142220433 is 334022241341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 143142220433 - 220 = 143141171857 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 143142220396 and 143142220405.

It is not an unprimeable number, because it can be changed into a prime (143142220493) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 940841 + ... + 1082342.

It is an arithmetic number, because the mean of its divisors is an integer number (18056917200).

Almost surely, 2143142220433 is an apocalyptic number.

It is an amenable number.

143142220433 is a deficient number, since it is larger than the sum of its proper divisors (1313117167).

143142220433 is a wasteful number, since it uses less digits than its factorization.

143142220433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2023831.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 143142220433 its reverse (334022241341), we get a palindrome (477164461774).

The spelling of 143142220433 in words is "one hundred forty-three billion, one hundred forty-two million, two hundred twenty thousand, four hundred thirty-three".

Divisors: 1 139 509 70751 2023183 281222437 1029800147 143142220433