Base | Representation |
---|---|
bin | 100000100010111111101011… |
… | …101111110001000101111011 |
3 | 200202211021101002222020001122 |
4 | 200202333223233301011323 |
5 | 122230220443020211103 |
6 | 1224234402333335455 |
7 | 42102456245446163 |
oct | 4042775357610573 |
9 | 622737332866048 |
10 | 143142330241403 |
11 | 416783597879a9 |
12 | 14079b3893758b |
13 | 61b435780554c |
14 | 274c1a90b35a3 |
15 | 11836d92e8b38 |
hex | 822febbf117b |
143142330241403 has 4 divisors (see below), whose sum is σ = 143142441179808. Its totient is φ = 143142219303000.
The previous prime is 143142330241367. The next prime is 143142330241423. The reversal of 143142330241403 is 304142033241341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 143142330241403 - 210 = 143142330240379 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (143142330241423) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53510723 + ... + 56122028.
It is an arithmetic number, because the mean of its divisors is an integer number (35785610294952).
Almost surely, 2143142330241403 is an apocalyptic number.
143142330241403 is a deficient number, since it is larger than the sum of its proper divisors (110938405).
143142330241403 is a wasteful number, since it uses less digits than its factorization.
143142330241403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110938404.
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 143142330241403 its reverse (304142033241341), we get a palindrome (447284363482744).
The spelling of 143142330241403 in words is "one hundred forty-three trillion, one hundred forty-two billion, three hundred thirty million, two hundred forty-one thousand, four hundred three".
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