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14314240001 = 115112436351
BaseRepresentation
bin11010101010011000…
…11111100000000001
31100221120202201211002
431111030133200001
5213303421140001
610324215501345
71014502014065
oct152514374001
940846681732
1014314240001
116086019416
122935987855
1314717543c9
1499b115aa5
1558ba0646b
hex35531f801

14314240001 has 4 divisors (see below), whose sum is σ = 14326677504. Its totient is φ = 14301802500.

The previous prime is 14314239997. The next prime is 14314240013. The reversal of 14314240001 is 10004241341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10004241341 = 76831130211.

It is a cyclic number.

It is not a de Polignac number, because 14314240001 - 22 = 14314239997 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (14314240051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6217025 + ... + 6219326.

It is an arithmetic number, because the mean of its divisors is an integer number (3581669376).

Almost surely, 214314240001 is an apocalyptic number.

It is an amenable number.

14314240001 is a deficient number, since it is larger than the sum of its proper divisors (12437503).

14314240001 is a wasteful number, since it uses less digits than its factorization.

14314240001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12437502.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 14314240001 its reverse (10004241341), we get a palindrome (24318481342).

The spelling of 14314240001 in words is "fourteen billion, three hundred fourteen million, two hundred forty thousand, one".

Divisors: 1 1151 12436351 14314240001