Base | Representation |
---|---|
bin | 1101000001001100101101… |
… | …0000110011011110111011 |
3 | 1212200102120002012102101221 |
4 | 3100103023100303132323 |
5 | 3334011031222212144 |
6 | 50235512134452511 |
7 | 3005112145514452 |
oct | 320231320633673 |
9 | 55612502172357 |
10 | 14314241210299 |
11 | 46196a9a9aa78 |
12 | 1732242504137 |
13 | 7caa9a3473c4 |
14 | 376b54b15b99 |
15 | 19c52d989d84 |
hex | d04cb4337bb |
14314241210299 has 4 divisors (see below), whose sum is σ = 14365181570760. Its totient is φ = 14263300849840.
The previous prime is 14314241210287. The next prime is 14314241210323. The reversal of 14314241210299 is 99201214241341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14314241210299 - 25 = 14314241210267 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14314241210219) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25470179809 + ... + 25470180370.
It is an arithmetic number, because the mean of its divisors is an integer number (3591295392690).
Almost surely, 214314241210299 is an apocalyptic number.
14314241210299 is a deficient number, since it is larger than the sum of its proper divisors (50940360461).
14314241210299 is an equidigital number, since it uses as much as digits as its factorization.
14314241210299 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50940360460.
The product of its (nonzero) digits is 124416, while the sum is 43.
The spelling of 14314241210299 in words is "fourteen trillion, three hundred fourteen billion, two hundred forty-one million, two hundred ten thousand, two hundred ninety-nine".
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