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1431451055035 = 5319235168097
BaseRepresentation
bin10100110101001001001…
…000011011001110111011
312001211211021200221011001
4110311021020123032323
5141423102432230120
63013333255545431
7205263456132031
oct24651110331673
95054737627131
101431451055035
11502090891461
121b151208b277
13a4ca67b5101
144d3d5656551
152737e365e0a
hex14d4921b3bb

1431451055035 has 8 divisors (see below), whose sum is σ = 1773152274816. Its totient is φ = 1108220171520.

The previous prime is 1431451055033. The next prime is 1431451055081. The reversal of 1431451055035 is 5305501541341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1431451055035 - 21 = 1431451055033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1431451054985 and 1431451055003.

It is not an unprimeable number, because it can be changed into a prime (1431451055033) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4617583894 + ... + 4617584203.

It is an arithmetic number, because the mean of its divisors is an integer number (221644034352).

Almost surely, 21431451055035 is an apocalyptic number.

1431451055035 is a deficient number, since it is larger than the sum of its proper divisors (341701219781).

1431451055035 is an equidigital number, since it uses as much as digits as its factorization.

1431451055035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9235168133.

The product of its (nonzero) digits is 90000, while the sum is 37.

Adding to 1431451055035 its reverse (5305501541341), we get a palindrome (6736952596376).

The spelling of 1431451055035 in words is "one trillion, four hundred thirty-one billion, four hundred fifty-one million, fifty-five thousand, thirty-five".

Divisors: 1 5 31 155 9235168097 46175840485 286290211007 1431451055035