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143145232435 = 5731163337213
BaseRepresentation
bin1000010101010000011…
…1101110100000110011
3111200111001000020112101
42011110013232200303
54321130134414220
6145432055041231
713225162254112
oct2052407564063
9450431006471
10143145232435
115578682a897
12238ab070217
131066339638a
146cdd23bc79
153acbe0230a
hex21541ee833

143145232435 has 16 divisors (see below), whose sum is σ = 174277590624. Its totient is φ = 112850019072.

The previous prime is 143145232427. The next prime is 143145232499. The reversal of 143145232435 is 534232541341.

It is a cyclic number.

It is not a de Polignac number, because 143145232435 - 23 = 143145232427 is a prime.

It is a super-3 number, since 3×1431452324353 (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 143145232394 and 143145232403.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 255889 + ... + 593101.

It is an arithmetic number, because the mean of its divisors is an integer number (10892349414).

Almost surely, 2143145232435 is an apocalyptic number.

143145232435 is a deficient number, since it is larger than the sum of its proper divisors (31132358189).

143145232435 is a wasteful number, since it uses less digits than its factorization.

143145232435 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 338454.

The product of its digits is 172800, while the sum is 37.

Adding to 143145232435 its reverse (534232541341), we get a palindrome (677377773776).

The spelling of 143145232435 in words is "one hundred forty-three billion, one hundred forty-five million, two hundred thirty-two thousand, four hundred thirty-five".

Divisors: 1 5 73 365 1163 5815 84899 337213 424495 1686065 24616549 123082745 392178719 1960893595 28629046487 143145232435