14314555345 has 4 divisors (see below), whose sum is σ = 17177466420. Its totient is φ = 11451644272.

The previous prime is 14314555303. The next prime is 14314555429. The reversal of 14314555345 is 54355541341.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54355541341 = 196817 ⋅276173.

It can be written as a sum of positive squares in 2 ways, for example, as 5272066881 + 9042488464 = 72609^2 + 95092^2 .

It is a cyclic number.

It is not a de Polignac number, because 14314555345 - 2⁹ = 14314554833 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14314555298 and 14314555307.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1431455530 + ... + 1431455539.

It is an arithmetic number, because the mean of its divisors is an integer number (4294366605).

Almost surely, 2^14314555345 is an apocalyptic number.

It is an amenable number.

14314555345 is a deficient number, since it is larger than the sum of its proper divisors (2862911075).

14314555345 is an equidigital number, since it uses as much as digits as its factorization.

14314555345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2862911074.

The product of its digits is 360000, while the sum is 40.

The spelling of 14314555345 in words is "fourteen billion, three hundred fourteen million, five hundred fifty-five thousand, three hundred forty-five".