143200321401 has 4 divisors (see below), whose sum is σ = 190933761872. Its totient is φ = 95466880932.

The previous prime is 143200321387. The next prime is 143200321469. The reversal of 143200321401 is 104123002341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 104123002341 = 3 ⋅34707667447.

It is not a de Polignac number, because 143200321401 - 2⁷ = 143200321273 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (143200321471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23866720231 + ... + 23866720236.

It is an arithmetic number, because the mean of its divisors is an integer number (47733440468).

Almost surely, 2^143200321401 is an apocalyptic number.

It is an amenable number.

143200321401 is a deficient number, since it is larger than the sum of its proper divisors (47733440471).

143200321401 is an equidigital number, since it uses as much as digits as its factorization.

143200321401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47733440470.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 143200321401 its reverse (104123002341), we get a palindrome (247323323742).

The spelling of 143200321401 in words is "one hundred forty-three billion, two hundred million, three hundred twenty-one thousand, four hundred one".