143200332011 has 4 divisors (see below), whose sum is σ = 156218544024. Its totient is φ = 130182120000.

The previous prime is 143200331983. The next prime is 143200332017. The reversal of 143200332011 is 110233002341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-143200332011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (143200332017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6509105990 + ... + 6509106011.

It is an arithmetic number, because the mean of its divisors is an integer number (39054636006).

Almost surely, 2^143200332011 is an apocalyptic number.

143200332011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

143200332011 is a deficient number, since it is larger than the sum of its proper divisors (13018212013).

143200332011 is a wasteful number, since it uses less digits than its factorization.

143200332011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13018212012.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 143200332011 its reverse (110233002341), we get a palindrome (253433334352).

The spelling of 143200332011 in words is "one hundred forty-three billion, two hundred million, three hundred thirty-two thousand, eleven".