1432011121 has 4 divisors (see below), whose sum is σ = 1432542832. Its totient is φ = 1431479412.

The previous prime is 1432011109. The next prime is 1432011131. The reversal of 1432011121 is 1211102341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1211102341 = 1877 ⋅645233.

It is a cyclic number.

It is not a de Polignac number, because 1432011121 - 2⁵ = 1432011089 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1432011095 and 1432011104.

It is not an unprimeable number, because it can be changed into a prime (1432011131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 261795 + ... + 267208.

It is an arithmetic number, because the mean of its divisors is an integer number (358135708).

Almost surely, 2^1432011121 is an apocalyptic number.

It is an amenable number.

1432011121 is a deficient number, since it is larger than the sum of its proper divisors (531711).

1432011121 is an equidigital number, since it uses as much as digits as its factorization.

1432011121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 531710.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 1432011121 is about 37841.9227973421. The cubic root of 1432011121 is about 1127.1510767353.

Adding to 1432011121 its reverse (1211102341), we get a palindrome (2643113462).

The spelling of 1432011121 in words is "one billion, four hundred thirty-two million, eleven thousand, one hundred twenty-one".