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143222131011 = 347740710337
BaseRepresentation
bin1000010101100010110…
…1000100100101000011
3111200200101201002112210
42011120231010211003
54321304331143021
6145443443153203
713230115012161
oct2053055044503
9450611632483
10143222131011
1155816182933
1223910975803
13106762abbab
146d09538231
153ad3a41e76
hex2158b44943

143222131011 has 4 divisors (see below), whose sum is σ = 190962841352. Its totient is φ = 95481420672.

The previous prime is 143222131009. The next prime is 143222131099. The reversal of 143222131011 is 110131222341.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 143222131011 - 21 = 143222131009 is a prime.

It is a super-2 number, since 2×1432221310112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (143222131411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23870355166 + ... + 23870355171.

It is an arithmetic number, because the mean of its divisors is an integer number (47740710338).

Almost surely, 2143222131011 is an apocalyptic number.

143222131011 is a deficient number, since it is larger than the sum of its proper divisors (47740710341).

143222131011 is an equidigital number, since it uses as much as digits as its factorization.

143222131011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47740710340.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 143222131011 its reverse (110131222341), we get a palindrome (253353353352).

The spelling of 143222131011 in words is "one hundred forty-three billion, two hundred twenty-two million, one hundred thirty-one thousand, eleven".

Divisors: 1 3 47740710337 143222131011