Base | Representation |
---|---|
bin | 1101000001101010011001… |
… | …1100101011010010000011 |
3 | 1212201012010200110200222011 |
4 | 3100122212130223102003 |
5 | 3334123343124000120 |
6 | 50243311204353351 |
7 | 3005513542043620 |
oct | 320324634532203 |
9 | 55635120420864 |
10 | 14322213500035 |
11 | 4622020161281 |
12 | 17338a83a5857 |
13 | 7cb76ac077cc |
14 | 3772ad849347 |
15 | 19c84880ec5a |
hex | d06a672b483 |
14322213500035 has 16 divisors (see below), whose sum is σ = 19655084203200. Its totient is φ = 9814350698496.
The previous prime is 14322213500029. The next prime is 14322213500047. The reversal of 14322213500035 is 53000531222341.
It is a cyclic number.
It is not a de Polignac number, because 14322213500035 - 23 = 14322213500027 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 137357590 + ... + 137461819.
It is an arithmetic number, because the mean of its divisors is an integer number (1228442762700).
Almost surely, 214322213500035 is an apocalyptic number.
14322213500035 is a deficient number, since it is larger than the sum of its proper divisors (5332870703165).
14322213500035 is a wasteful number, since it uses less digits than its factorization.
14322213500035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 274820910.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 14322213500035 its reverse (53000531222341), we get a palindrome (67322744722376).
The spelling of 14322213500035 in words is "fourteen trillion, three hundred twenty-two billion, two hundred thirteen million, five hundred thousand, thirty-five".
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