Base | Representation |
---|---|
bin | 1000010101100011010… |
… | …1000011010100111011 |
3 | 111200200112122101021011 |
4 | 2011120311003110323 |
5 | 4321310400114120 |
6 | 145444000054351 |
7 | 13230141544315 |
oct | 2053065032473 |
9 | 450615571234 |
10 | 143224223035 |
11 | 55817381683 |
12 | 239116043b7 |
13 | 1067686218a |
14 | 6d099207b5 |
15 | 3ad3d06c5a |
hex | 2158d4353b |
143224223035 has 4 divisors (see below), whose sum is σ = 171869067648. Its totient is φ = 114579378424.
The previous prime is 143224223027. The next prime is 143224223047. The reversal of 143224223035 is 530322422341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 143224223035 - 23 = 143224223027 is a prime.
It is a super-2 number, since 2×1432242230352 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 143224222988 and 143224223006.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14322422299 + ... + 14322422308.
It is an arithmetic number, because the mean of its divisors is an integer number (42967266912).
Almost surely, 2143224223035 is an apocalyptic number.
143224223035 is a deficient number, since it is larger than the sum of its proper divisors (28644844613).
143224223035 is an equidigital number, since it uses as much as digits as its factorization.
143224223035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28644844612.
The product of its (nonzero) digits is 34560, while the sum is 31.
Adding to 143224223035 its reverse (530322422341), we get a palindrome (673546645376).
The spelling of 143224223035 in words is "one hundred forty-three billion, two hundred twenty-four million, two hundred twenty-three thousand, thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.205 sec. • engine limits •