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143231444401 = 213623670487
BaseRepresentation
bin1000010101100101000…
…0100110010110110001
3111200201001020021010011
42011121100212112301
54321314222210101
6145444414534521
713230260122003
oct2053120462661
9450631207104
10143231444401
1155820464151
1223913b07441
13106781c0086
146d0a880373
153ad4781751
hex21594265b1

143231444401 has 4 divisors (see below), whose sum is σ = 143232328512. Its totient is φ = 143230560292.

The previous prime is 143231444381. The next prime is 143231444431. The reversal of 143231444401 is 104444132341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 143231444401 - 211 = 143231442353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (143231444431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121621 + ... + 548866.

It is an arithmetic number, because the mean of its divisors is an integer number (35808082128).

Almost surely, 2143231444401 is an apocalyptic number.

It is an amenable number.

143231444401 is a deficient number, since it is larger than the sum of its proper divisors (884111).

143231444401 is an equidigital number, since it uses as much as digits as its factorization.

143231444401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 884110.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 143231444401 its reverse (104444132341), we get a palindrome (247675576742).

The spelling of 143231444401 in words is "one hundred forty-three billion, two hundred thirty-one million, four hundred forty-four thousand, four hundred one".

Divisors: 1 213623 670487 143231444401