Base | Representation |
---|---|
bin | 1101000001101110001000… |
… | …0110111011001110001011 |
3 | 1212201021201102220021021122 |
4 | 3100123202012323032023 |
5 | 3334132420343243430 |
6 | 50243554402025455 |
7 | 3005550414603212 |
oct | 320334206731613 |
9 | 55637642807248 |
10 | 14323214431115 |
11 | 4622494160647 |
12 | 1733b2764828b |
13 | 7cb89a3ac715 |
14 | 37736675a079 |
15 | 19c8a6626ee5 |
hex | d06e21bb38b |
14323214431115 has 8 divisors (see below), whose sum is σ = 17214178695408. Its totient is φ = 11441023959520.
The previous prime is 14323214431093. The next prime is 14323214431153. The reversal of 14323214431115 is 51113441232341.
14323214431115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14323214431115 - 212 = 14323214427019 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2193444581 + ... + 2193451110.
It is an arithmetic number, because the mean of its divisors is an integer number (2151772336926).
Almost surely, 214323214431115 is an apocalyptic number.
14323214431115 is a deficient number, since it is larger than the sum of its proper divisors (2890964264293).
14323214431115 is an equidigital number, since it uses as much as digits as its factorization.
14323214431115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4386896349.
The product of its digits is 34560, while the sum is 35.
Adding to 14323214431115 its reverse (51113441232341), we get a palindrome (65436655663456).
The spelling of 14323214431115 in words is "fourteen trillion, three hundred twenty-three billion, two hundred fourteen million, four hundred thirty-one thousand, one hundred fifteen".
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