Base | Representation |
---|---|
bin | 1101000001101110001111… |
… | …1101011111111010100011 |
3 | 1212201021210121101110112112 |
4 | 3100123203331133322203 |
5 | 3334133001322430103 |
6 | 50244001432145535 |
7 | 3005551243033100 |
oct | 320334375377243 |
9 | 55637717343475 |
10 | 14323245514403 |
11 | 46224aa760a11 |
12 | 1733b35b382ab |
13 | 7cb8a39737b7 |
14 | 37736a92baa7 |
15 | 19c8a9216cd8 |
hex | d06e3f5fea3 |
14323245514403 has 6 divisors (see below), whose sum is σ = 16661734578036. Its totient is φ = 12277067583732.
The previous prime is 14323245514339. The next prime is 14323245514439. The reversal of 14323245514403 is 30441554232341.
It is not a de Polignac number, because 14323245514403 - 26 = 14323245514339 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14323245514453) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 146155566425 + ... + 146155566522.
It is an arithmetic number, because the mean of its divisors is an integer number (2776955763006).
Almost surely, 214323245514403 is an apocalyptic number.
14323245514403 is a deficient number, since it is larger than the sum of its proper divisors (2338489063633).
14323245514403 is an equidigital number, since it uses as much as digits as its factorization.
14323245514403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 292311132961 (or 292311132954 counting only the distinct ones).
The product of its (nonzero) digits is 691200, while the sum is 41.
Adding to 14323245514403 its reverse (30441554232341), we get a palindrome (44764799746744).
The spelling of 14323245514403 in words is "fourteen trillion, three hundred twenty-three billion, two hundred forty-five million, five hundred fourteen thousand, four hundred three".
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