Base | Representation |
---|---|
bin | 1101000001101110010001… |
… | …0110010000010101101011 |
3 | 1212201021211001121011212111 |
4 | 3100123210112100111223 |
5 | 3334133010003113303 |
6 | 50244002223223151 |
7 | 3005551352142562 |
oct | 320334426202553 |
9 | 55637731534774 |
10 | 14323252004203 |
11 | 462250339388a |
12 | 1733b38147ab7 |
13 | 7cb8a510670c |
14 | 37736b73abd9 |
15 | 19c8a9a99b6d |
hex | d06e459056b |
14323252004203 has 4 divisors (see below), whose sum is σ = 14323260633040. Its totient is φ = 14323243375368.
The previous prime is 14323252004189. The next prime is 14323252004207. The reversal of 14323252004203 is 30240025232341.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 14323252004203 - 229 = 14322715133291 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14323252004207) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 949983 + ... + 5435896.
It is an arithmetic number, because the mean of its divisors is an integer number (3580815158260).
Almost surely, 214323252004203 is an apocalyptic number.
14323252004203 is a deficient number, since it is larger than the sum of its proper divisors (8628837).
14323252004203 is an equidigital number, since it uses as much as digits as its factorization.
14323252004203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8628836.
The product of its (nonzero) digits is 34560, while the sum is 31.
Adding to 14323252004203 its reverse (30240025232341), we get a palindrome (44563277236544).
The spelling of 14323252004203 in words is "fourteen trillion, three hundred twenty-three billion, two hundred fifty-two million, four thousand, two hundred three".
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