Base | Representation |
---|---|
bin | 11010101011011110… |
… | …11110011000000001 |
3 | 1100222020000122021201 |
4 | 31111233132120001 |
5 | 213313243113213 |
6 | 10325144221201 |
7 | 1014642660043 |
oct | 152557363001 |
9 | 40866018251 |
10 | 14323410433 |
11 | 6090212292 |
12 | 2938a6a801 |
13 | 14736154b7 |
14 | 99c421a93 |
15 | 58c7186dd |
hex | 355bde601 |
14323410433 has 4 divisors (see below), whose sum is σ = 15077274160. Its totient is φ = 13569546708.
The previous prime is 14323410397. The next prime is 14323410457. The reversal of 14323410433 is 33401432341.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14323410433 - 217 = 14323279361 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14323410833) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 376931835 + ... + 376931872.
It is an arithmetic number, because the mean of its divisors is an integer number (3769318540).
Almost surely, 214323410433 is an apocalyptic number.
It is an amenable number.
14323410433 is a deficient number, since it is larger than the sum of its proper divisors (753863727).
14323410433 is an equidigital number, since it uses as much as digits as its factorization.
14323410433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 753863726.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 14323410433 its reverse (33401432341), we get a palindrome (47724842774).
The spelling of 14323410433 in words is "fourteen billion, three hundred twenty-three million, four hundred ten thousand, four hundred thirty-three".
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