Base | Representation |
---|---|
bin | 1000010101100101101… |
… | …1111111010100100001 |
3 | 111200201020211221220211 |
4 | 2011121123333110201 |
5 | 4321321003231431 |
6 | 145445002534121 |
7 | 13230324366040 |
oct | 2053133772441 |
9 | 450636757824 |
10 | 143234430241 |
11 | 55822113491 |
12 | 23914b07341 |
13 | 106789c7146 |
14 | 6d0b01a557 |
15 | 3ad4b712b1 |
hex | 21596ff521 |
143234430241 has 8 divisors (see below), whose sum is σ = 165668739264. Its totient is φ = 121293183120.
The previous prime is 143234430181. The next prime is 143234430263. The reversal of 143234430241 is 142034432341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 143234430241 - 223 = 143226041633 is a prime.
It is a super-2 number, since 2×1432344302412 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (143234430281) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 123264850 + ... + 123266011.
It is an arithmetic number, because the mean of its divisors is an integer number (20708592408).
Almost surely, 2143234430241 is an apocalyptic number.
It is an amenable number.
143234430241 is a deficient number, since it is larger than the sum of its proper divisors (22434309023).
143234430241 is an equidigital number, since it uses as much as digits as its factorization.
143234430241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 246530951.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 143234430241 its reverse (142034432341), we get a palindrome (285268862582).
The spelling of 143234430241 in words is "one hundred forty-three billion, two hundred thirty-four million, four hundred thirty thousand, two hundred forty-one".
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