Base | Representation |
---|---|
bin | 1101000001110001001000… |
… | …1000101110100101011011 |
3 | 1212201100210121010002010110 |
4 | 3100130102020232211123 |
5 | 3334141043133210021 |
6 | 50244210344415403 |
7 | 3005606400605631 |
oct | 320342210564533 |
9 | 55640717102113 |
10 | 14324020210011 |
11 | 4622867a89216 |
12 | 1734111477563 |
13 | 7cb998306a75 |
14 | 37740178b351 |
15 | 19c902241476 |
hex | d071222e95b |
14324020210011 has 4 divisors (see below), whose sum is σ = 19098693613352. Its totient is φ = 9549346806672.
The previous prime is 14324020209979. The next prime is 14324020210021. The reversal of 14324020210011 is 11001202042341.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 14324020210011 - 25 = 14324020209979 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 14324020210011.
It is not an unprimeable number, because it can be changed into a prime (14324020210021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2387336701666 + ... + 2387336701671.
It is an arithmetic number, because the mean of its divisors is an integer number (4774673403338).
Almost surely, 214324020210011 is an apocalyptic number.
14324020210011 is a deficient number, since it is larger than the sum of its proper divisors (4774673403341).
14324020210011 is an equidigital number, since it uses as much as digits as its factorization.
14324020210011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4774673403340.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 14324020210011 its reverse (11001202042341), we get a palindrome (25325222252352).
The spelling of 14324020210011 in words is "fourteen trillion, three hundred twenty-four billion, twenty million, two hundred ten thousand, eleven".
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