14324131110451 has 4 divisors (see below), whose sum is σ = 14496711003432. Its totient is φ = 14151551217472.

The previous prime is 14324131110431. The next prime is 14324131110461. The reversal of 14324131110451 is 15401113142341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14324131110451 - 2³⁵ = 14289771372083 is a prime.

It is a super-2 number, since 2×14324131110451² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14324131110431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86289946366 + ... + 86289946531.

It is an arithmetic number, because the mean of its divisors is an integer number (3624177750858).

Almost surely, 2^{14324131110451} is an apocalyptic number.

14324131110451 is a deficient number, since it is larger than the sum of its proper divisors (172579892981).

14324131110451 is an equidigital number, since it uses as much as digits as its factorization.

14324131110451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 172579892980.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 14324131110451 its reverse (15401113142341), we get a palindrome (29725244252792).

The spelling of 14324131110451 in words is "fourteen trillion, three hundred twenty-four billion, one hundred thirty-one million, one hundred ten thousand, four hundred fifty-one".