Base | Representation |
---|---|
bin | 1101000001110001111111… |
… | …1100111110011110100011 |
3 | 1212201101101202021202111011 |
4 | 3100130133330332132203 |
5 | 3334142032003313103 |
6 | 50244245345001351 |
7 | 3005615214100546 |
oct | 320343774763643 |
9 | 55641352252434 |
10 | 14324252010403 |
11 | 4622976911295 |
12 | 1734177023257 |
13 | 7cba0434666a |
14 | 37742448a85d |
15 | 19c91777cd6d |
hex | d071ff3e7a3 |
14324252010403 has 4 divisors (see below), whose sum is σ = 14324356364400. Its totient is φ = 14324147656408.
The previous prime is 14324252010401. The next prime is 14324252010487. The reversal of 14324252010403 is 30401025242341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14324252010403 - 21 = 14324252010401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14324252010401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51970828 + ... + 52245721.
It is an arithmetic number, because the mean of its divisors is an integer number (3581089091100).
Almost surely, 214324252010403 is an apocalyptic number.
14324252010403 is a deficient number, since it is larger than the sum of its proper divisors (104353997).
14324252010403 is a wasteful number, since it uses less digits than its factorization.
14324252010403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 104353996.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 14324252010403 its reverse (30401025242341), we get a palindrome (44725277252744).
The spelling of 14324252010403 in words is "fourteen trillion, three hundred twenty-four billion, two hundred fifty-two million, ten thousand, four hundred three".
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