Base | Representation |
---|---|
bin | 1101000001110101100100… |
… | …0111010000000010111011 |
3 | 1212201110212120210201220211 |
4 | 3100131121013100002323 |
5 | 3334201013004130430 |
6 | 50244524443331551 |
7 | 3005651040315523 |
oct | 320353107200273 |
9 | 55643776721824 |
10 | 14325211005115 |
11 | 46233191781aa |
12 | 17343a4220bb7 |
13 | 7cbb27c2755a |
14 | 3774b59a2683 |
15 | 19c971a5e72a |
hex | d07591d00bb |
14325211005115 has 4 divisors (see below), whose sum is σ = 17190253206144. Its totient is φ = 11460168804088.
The previous prime is 14325211005109. The next prime is 14325211005151. The reversal of 14325211005115 is 51150011252341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14325211005115 - 27 = 14325211004987 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1432521100507 + ... + 1432521100516.
It is an arithmetic number, because the mean of its divisors is an integer number (4297563301536).
Almost surely, 214325211005115 is an apocalyptic number.
14325211005115 is a deficient number, since it is larger than the sum of its proper divisors (2865042201029).
14325211005115 is an equidigital number, since it uses as much as digits as its factorization.
14325211005115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2865042201028.
The product of its (nonzero) digits is 6000, while the sum is 31.
Adding to 14325211005115 its reverse (51150011252341), we get a palindrome (65475222257456).
The spelling of 14325211005115 in words is "fourteen trillion, three hundred twenty-five billion, two hundred eleven million, five thousand, one hundred fifteen".
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