14325315551251 has 4 divisors (see below), whose sum is σ = 14819291949600. Its totient is φ = 13831339152904.

The previous prime is 14325315551219. The next prime is 14325315551257. The reversal of 14325315551251 is 15215551352341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14325315551251 - 2⁵ = 14325315551219 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14325315551198 and 14325315551207.

It is not an unprimeable number, because it can be changed into a prime (14325315551257) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 246988199131 + ... + 246988199188.

It is an arithmetic number, because the mean of its divisors is an integer number (3704822987400).

Almost surely, 2^{14325315551251} is an apocalyptic number.

14325315551251 is a deficient number, since it is larger than the sum of its proper divisors (493976398349).

14325315551251 is an equidigital number, since it uses as much as digits as its factorization.

14325315551251 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 493976398348.

The product of its digits is 450000, while the sum is 43.

The spelling of 14325315551251 in words is "fourteen trillion, three hundred twenty-five billion, three hundred fifteen million, five hundred fifty-one thousand, two hundred fifty-one".