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14331055531 = 131519372559
BaseRepresentation
bin11010101100011001…
…01000110110101011
31100222202102001101111
431112030220312223
5213322222234111
610330020131151
71015064651002
oct152614506653
940882361344
1014331055531
116094564151
12293b536ab7
131475091220
1499d451c39
1558d228a21
hex356328dab

14331055531 has 8 divisors (see below), whose sum is σ = 15434672960. Its totient is φ = 13227613632.

The previous prime is 14331055511. The next prime is 14331055549. The reversal of 14331055531 is 13555013341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14331055531 - 221 = 14328958379 is a prime.

It is a super-2 number, since 2×143310555312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14331055493 and 14331055502.

It is not an unprimeable number, because it can be changed into a prime (14331055511) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 161230 + ... + 233788.

It is an arithmetic number, because the mean of its divisors is an integer number (1929334120).

Almost surely, 214331055531 is an apocalyptic number.

14331055531 is a deficient number, since it is larger than the sum of its proper divisors (1103617429).

14331055531 is a wasteful number, since it uses less digits than its factorization.

14331055531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 87765.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 14331055531 its reverse (13555013341), we get a palindrome (27886068872).

The spelling of 14331055531 in words is "fourteen billion, three hundred thirty-one million, fifty-five thousand, five hundred thirty-one".

Divisors: 1 13 15193 72559 197509 943267 1102388887 14331055531