Base | Representation |
---|---|
bin | 1101000010001110000011… |
… | …1010001110101000111001 |
3 | 1212202002211200112200200010 |
4 | 3100203200322032220321 |
5 | 3334302443232311103 |
6 | 50251533015132133 |
7 | 3006302655132423 |
oct | 320434072165071 |
9 | 55662750480603 |
10 | 14331784260153 |
11 | 4626091649a88 |
12 | 1735719674049 |
13 | 7cc6349b6689 |
14 | 37793a995813 |
15 | 19cc08b80903 |
hex | d08e0e8ea39 |
14331784260153 has 4 divisors (see below), whose sum is σ = 19109045680208. Its totient is φ = 9554522840100.
The previous prime is 14331784260151. The next prime is 14331784260197. The reversal of 14331784260153 is 35106248713341.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 14331784260153 - 21 = 14331784260151 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14331784260151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2388630710023 + ... + 2388630710028.
It is an arithmetic number, because the mean of its divisors is an integer number (4777261420052).
Almost surely, 214331784260153 is an apocalyptic number.
It is an amenable number.
14331784260153 is a deficient number, since it is larger than the sum of its proper divisors (4777261420055).
14331784260153 is an equidigital number, since it uses as much as digits as its factorization.
14331784260153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4777261420054.
The product of its (nonzero) digits is 1451520, while the sum is 48.
The spelling of 14331784260153 in words is "fourteen trillion, three hundred thirty-one billion, seven hundred eighty-four million, two hundred sixty thousand, one hundred fifty-three".
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