14332041131 has 8 divisors (see below), whose sum is σ = 15585240960. Its totient is φ = 13124412288.

The previous prime is 14332041121. The next prime is 14332041133. The reversal of 14332041131 is 13114023341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14332041131 - 2⁶ = 14332041067 is a prime.

It is a super-2 number, since 2×14332041131² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14332041097 and 14332041106.

It is not an unprimeable number, because it can be changed into a prime (14332041133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11392091 + ... + 11393348.

It is an arithmetic number, because the mean of its divisors is an integer number (1948155120).

Almost surely, 2^14332041131 is an apocalyptic number.

14332041131 is a deficient number, since it is larger than the sum of its proper divisors (1253199829).

14332041131 is a wasteful number, since it uses less digits than its factorization.

14332041131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22785493.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 14332041131 its reverse (13114023341), we get a palindrome (27446064472).

The spelling of 14332041131 in words is "fourteen billion, three hundred thirty-two million, forty-one thousand, one hundred thirty-one".