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14332042441 = 139103108219
BaseRepresentation
bin11010101100100000…
…11001110011001001
31100222211021012011201
431112100121303021
5213323000324231
610330053224201
71015106231203
oct152620316311
940884235151
1014332042441
116095078682
12293b932061
1314753484b2
1499d62b773
1558d371161
hex356419cc9

14332042441 has 4 divisors (see below), whose sum is σ = 14435150800. Its totient is φ = 14228934084.

The previous prime is 14332042421. The next prime is 14332042471. The reversal of 14332042441 is 14424023341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14332042441 - 27 = 14332042313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14332042421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51553971 + ... + 51554248.

It is an arithmetic number, because the mean of its divisors is an integer number (3608787700).

Almost surely, 214332042441 is an apocalyptic number.

It is an amenable number.

14332042441 is a deficient number, since it is larger than the sum of its proper divisors (103108359).

14332042441 is a wasteful number, since it uses less digits than its factorization.

14332042441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103108358.

The product of its (nonzero) digits is 9216, while the sum is 28.

Adding to 14332042441 its reverse (14424023341), we get a palindrome (28756065782).

It can be divided in two parts, 143320 and 42441, that added together give a square (185761 = 4312).

The spelling of 14332042441 in words is "fourteen billion, three hundred thirty-two million, forty-two thousand, four hundred forty-one".

Divisors: 1 139 103108219 14332042441