Base | Representation |
---|---|
bin | 1101000010010010101100… |
… | …1010111001100011110011 |
3 | 1212202020001111220011100022 |
4 | 3100210223022321203303 |
5 | 3334313021204103433 |
6 | 50252300402514055 |
7 | 3006345564023516 |
oct | 320445312714363 |
9 | 55666044804308 |
10 | 14333030144243 |
11 | 4626670945158 |
12 | 1735a0696592b |
13 | 7cc7a2b549b5 |
14 | 377a1822ad7d |
15 | 19cc7d231698 |
hex | d092b2b98f3 |
14333030144243 has 16 divisors (see below), whose sum is σ = 14833000324800. Its totient is φ = 13833443164800.
The previous prime is 14333030144159. The next prime is 14333030144261. The reversal of 14333030144243 is 34244103033341.
14333030144243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14333030144243 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14333030147243) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1538039138 + ... + 1538048456.
It is an arithmetic number, because the mean of its divisors is an integer number (927062520300).
Almost surely, 214333030144243 is an apocalyptic number.
14333030144243 is a deficient number, since it is larger than the sum of its proper divisors (499970180557).
14333030144243 is an equidigital number, since it uses as much as digits as its factorization.
14333030144243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24142.
The product of its (nonzero) digits is 124416, while the sum is 35.
Adding to 14333030144243 its reverse (34244103033341), we get a palindrome (48577133177584).
The spelling of 14333030144243 in words is "fourteen trillion, three hundred thirty-three billion, thirty million, one hundred forty-four thousand, two hundred forty-three".
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