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14333113 = 64322291
BaseRepresentation
bin110110101011…
…010010111001
3222222012100001
4312223102321
512132124423
61231113001
7232554334
oct66532271
928865301
1014333113
1180aa753
124972761
132c7ac42
141c9161b
1513d1cad
hexdab4b9

14333113 has 4 divisors (see below), whose sum is σ = 14356048. Its totient is φ = 14310180.

The previous prime is 14333107. The next prime is 14333131. The reversal of 14333113 is 31133341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31133341 = 171831373.

It is a cyclic number.

It is not a de Polignac number, because 14333113 - 221 = 12235961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14333153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10503 + ... + 11788.

It is an arithmetic number, because the mean of its divisors is an integer number (3589012).

Almost surely, 214333113 is an apocalyptic number.

It is an amenable number.

14333113 is a deficient number, since it is larger than the sum of its proper divisors (22935).

14333113 is an equidigital number, since it uses as much as digits as its factorization.

14333113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22934.

The product of its digits is 324, while the sum is 19.

The square root of 14333113 is about 3785.9097981859. The cubic root of 14333113 is about 242.9108096755.

Adding to 14333113 its reverse (31133341), we get a palindrome (45466454).

The spelling of 14333113 in words is "fourteen million, three hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 643 22291 14333113