Base | Representation |
---|---|
bin | 1000010110000010010… |
… | …0000111111101111011 |
3 | 111201000120211220100111 |
4 | 2011200210013331323 |
5 | 4322042111101243 |
6 | 145504513445151 |
7 | 13233305631436 |
oct | 2054044077573 |
9 | 451016756314 |
10 | 143354003323 |
11 | 55883663513 |
12 | 23948b707b7 |
13 | 1069770194b |
14 | 6d1cc6481d |
15 | 3ae03e039d |
hex | 2160907f7b |
143354003323 has 4 divisors (see below), whose sum is σ = 145168611040. Its totient is φ = 141539395608.
The previous prime is 143354003321. The next prime is 143354003329. The reversal of 143354003323 is 323300453341.
143354003323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 143354003323 - 21 = 143354003321 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (143354003321) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 907303740 + ... + 907303897.
It is an arithmetic number, because the mean of its divisors is an integer number (36292152760).
Almost surely, 2143354003323 is an apocalyptic number.
143354003323 is a deficient number, since it is larger than the sum of its proper divisors (1814607717).
143354003323 is an equidigital number, since it uses as much as digits as its factorization.
143354003323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1814607716.
The product of its (nonzero) digits is 38880, while the sum is 31.
Adding to 143354003323 its reverse (323300453341), we get a palindrome (466654456664).
The spelling of 143354003323 in words is "one hundred forty-three billion, three hundred fifty-four million, three thousand, three hundred twenty-three".
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