14340113 has 4 divisors (see below), whose sum is σ = 14673648. Its totient is φ = 14006580.

The previous prime is 14340107. The next prime is 14340133. The reversal of 14340113 is 31104341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14340113 - 2⁴ = 14340097 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14340091 and 14340100.

It is not an unprimeable number, because it can be changed into a prime (14340133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166703 + ... + 166788.

It is an arithmetic number, because the mean of its divisors is an integer number (3668412).

Almost surely, 2^14340113 is an apocalyptic number.

It is an amenable number.

14340113 is a deficient number, since it is larger than the sum of its proper divisors (333535).

14340113 is an equidigital number, since it uses as much as digits as its factorization.

14340113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 333534.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 14340113 is about 3786.8341658964. The cubic root of 14340113 is about 242.9503474677.

Adding to 14340113 its reverse (31104341), we get a palindrome (45444454).

The spelling of 14340113 in words is "fourteen million, three hundred forty thousand, one hundred thirteen".