14340253540131 has 12 divisors (see below), whose sum is σ = 20713851840240. Its totient is φ = 9560098742640.

The previous prime is 14340253540121. The next prime is 14340253540133. The reversal of 14340253540131 is 13104535204341.

14340253540131 is a `hidden beast` number, since 1 + 4 + 34 + 0 + 2 + 53 + 540 + 1 + 31 = 666.

It is not a de Polignac number, because 14340253540131 - 2¹³ = 14340253531939 is a prime.

It is a super-2 number, since 2×14340253540131² (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (14340253540133) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4549440 + ... + 7026941.

It is an arithmetic number, because the mean of its divisors is an integer number (1726154320020).

Almost surely, 2^{14340253540131} is an apocalyptic number.

14340253540131 is a deficient number, since it is larger than the sum of its proper divisors (6373598300109).

14340253540131 is a wasteful number, since it uses less digits than its factorization.

14340253540131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11714026 (or 11714023 counting only the distinct ones).

The product of its (nonzero) digits is 86400, while the sum is 36.

Adding to 14340253540131 its reverse (13104535204341), we get a palindrome (27444788744472).

The spelling of 14340253540131 in words is "fourteen trillion, three hundred forty billion, two hundred fifty-three million, five hundred forty thousand, one hundred thirty-one".