Base | Representation |
---|---|
bin | 1101000010110000110101… |
… | …1000110111110010100001 |
3 | 1212202222221100012000022211 |
4 | 3100230031120313302201 |
5 | 3334431103312100441 |
6 | 50300115245402121 |
7 | 3010053222206320 |
oct | 320541530676241 |
9 | 55688840160284 |
10 | 14341120425121 |
11 | 462a0426759a6 |
12 | 17374a4269341 |
13 | 800491cb7849 |
14 | 3781848b60b7 |
15 | 19d0a3611a81 |
hex | d0b0d637ca1 |
14341120425121 has 8 divisors (see below), whose sum is σ = 16389956271744. Its totient is φ = 12292310667840.
The previous prime is 14341120425109. The next prime is 14341120425143. The reversal of 14341120425121 is 12152402114341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14341120425121 - 25 = 14341120425089 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14341120426121) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5329885 + ... + 7555786.
It is an arithmetic number, because the mean of its divisors is an integer number (2048744533968).
Almost surely, 214341120425121 is an apocalyptic number.
It is an amenable number.
14341120425121 is a deficient number, since it is larger than the sum of its proper divisors (2048835846623).
14341120425121 is a wasteful number, since it uses less digits than its factorization.
14341120425121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13044671.
The product of its (nonzero) digits is 7680, while the sum is 31.
Adding to 14341120425121 its reverse (12152402114341), we get a palindrome (26493522539462).
The spelling of 14341120425121 in words is "fourteen trillion, three hundred forty-one billion, one hundred twenty million, four hundred twenty-five thousand, one hundred twenty-one".
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