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143411403 = 347803801
BaseRepresentation
bin10001000110001…
…00100011001011
3100222212001110110
420203010203023
5243203131103
622121445403
73360656022
oct1043044313
9328761413
10143411403
1173a52123
1240040863
1323933025
14150918b9
15c8cc403
hex88c48cb

143411403 has 4 divisors (see below), whose sum is σ = 191215208. Its totient is φ = 95607600.

The previous prime is 143411381. The next prime is 143411419. The reversal of 143411403 is 304114341.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 143411403 - 217 = 143280331 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 143411403.

It is not an unprimeable number, because it can be changed into a prime (143411453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23901898 + ... + 23901903.

It is an arithmetic number, because the mean of its divisors is an integer number (47803802).

Almost surely, 2143411403 is an apocalyptic number.

143411403 is a deficient number, since it is larger than the sum of its proper divisors (47803805).

143411403 is an equidigital number, since it uses as much as digits as its factorization.

143411403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47803804.

The product of its (nonzero) digits is 576, while the sum is 21.

The square root of 143411403 is about 11975.4500124212. The cubic root of 143411403 is about 523.4331552140.

Adding to 143411403 its reverse (304114341), we get a palindrome (447525744).

The spelling of 143411403 in words is "one hundred forty-three million, four hundred eleven thousand, four hundred three".

Divisors: 1 3 47803801 143411403