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14341220425555 = 52868244085111
BaseRepresentation
bin1101000010110001001101…
…0110010101111101010011
31212210000012022100120010121
43100230103112111331103
53334431304412104210
650300133221011111
73010055545202632
oct320542326257523
955700168316117
1014341220425555
11462a094067791
121737511853a97
138004a992b5ba
14378193ca7519
1519d0ac2b66da
hexd0b13595f53

14341220425555 has 4 divisors (see below), whose sum is σ = 17209464510672. Its totient is φ = 11472976340440.

The previous prime is 14341220425451. The next prime is 14341220425561. The reversal of 14341220425555 is 55552402214341.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 14341220425555 - 215 = 14341220392787 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1434122042551 + ... + 1434122042560.

It is an arithmetic number, because the mean of its divisors is an integer number (4302366127668).

Almost surely, 214341220425555 is an apocalyptic number.

14341220425555 is a deficient number, since it is larger than the sum of its proper divisors (2868244085117).

14341220425555 is an equidigital number, since it uses as much as digits as its factorization.

14341220425555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2868244085116.

The product of its (nonzero) digits is 960000, while the sum is 43.

Adding to 14341220425555 its reverse (55552402214341), we get a palindrome (69893622639896).

The spelling of 14341220425555 in words is "fourteen trillion, three hundred forty-one billion, two hundred twenty million, four hundred twenty-five thousand, five hundred fifty-five".

Divisors: 1 5 2868244085111 14341220425555