14341401211331 has 4 divisors (see below), whose sum is σ = 14341620661464. Its totient is φ = 14341181761200.

The previous prime is 14341401211297. The next prime is 14341401211339. The reversal of 14341401211331 is 13311210414341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14341401211331 is a prime.

It is a super-2 number, since 2×14341401211331² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14341401211294 and 14341401211303.

It is not an unprimeable number, because it can be changed into a prime (14341401211339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 109627010 + ... + 109757751.

It is an arithmetic number, because the mean of its divisors is an integer number (3585405165366).

Almost surely, 2^{14341401211331} is an apocalyptic number.

14341401211331 is a deficient number, since it is larger than the sum of its proper divisors (219450133).

14341401211331 is an equidigital number, since it uses as much as digits as its factorization.

14341401211331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 219450132.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 14341401211331 its reverse (13311210414341), we get a palindrome (27652611625672).

The spelling of 14341401211331 in words is "fourteen trillion, three hundred forty-one billion, four hundred one million, two hundred eleven thousand, three hundred thirty-one".