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14342035 = 52868407
BaseRepresentation
bin110110101101…
…011110010011
3222222122120111
4312231132103
512132421120
61231222151
7232622341
oct66553623
928878514
1014342035
118106424
124977957
132c82016
141c94991
1513d475a
hexdad793

14342035 has 4 divisors (see below), whose sum is σ = 17210448. Its totient is φ = 11473624.

The previous prime is 14342021. The next prime is 14342047. The reversal of 14342035 is 53024341.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53024341 = 70175641.

It is a cyclic number.

It is not a de Polignac number, because 14342035 - 27 = 14341907 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14341997 and 14342015.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1434199 + ... + 1434208.

It is an arithmetic number, because the mean of its divisors is an integer number (4302612).

Almost surely, 214342035 is an apocalyptic number.

14342035 is a deficient number, since it is larger than the sum of its proper divisors (2868413).

14342035 is an equidigital number, since it uses as much as digits as its factorization.

14342035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2868412.

The product of its (nonzero) digits is 1440, while the sum is 22.

The square root of 14342035 is about 3787.0879313795. The cubic root of 14342035 is about 242.9612011643.

Adding to 14342035 its reverse (53024341), we get a palindrome (67366376).

The spelling of 14342035 in words is "fourteen million, three hundred forty-two thousand, thirty-five".

Divisors: 1 5 2868407 14342035