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14342315323433 = 41934229869507
BaseRepresentation
bin1101000010110101010010…
…0111000011000000101001
31212210010000121121010122212
43100231110213003000221
53334441030210322213
650300434012254505
73010124641526006
oct320552447030051
955703017533585
1014342315323433
11462a5a6107769
121737778471435
13800622713b76
143782594788ad
1519d1234909a8
hexd0b549c3029

14342315323433 has 4 divisors (see below), whose sum is σ = 14376545193360. Its totient is φ = 14308085453508.

The previous prime is 14342315323421. The next prime is 14342315323439. The reversal of 14342315323433 is 33432351324341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14342315323433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14342315323439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17114934335 + ... + 17114935172.

It is an arithmetic number, because the mean of its divisors is an integer number (3594136298340).

Almost surely, 214342315323433 is an apocalyptic number.

It is an amenable number.

14342315323433 is a deficient number, since it is larger than the sum of its proper divisors (34229869927).

14342315323433 is an equidigital number, since it uses as much as digits as its factorization.

14342315323433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34229869926.

The product of its digits is 933120, while the sum is 41.

Adding to 14342315323433 its reverse (33432351324341), we get a palindrome (47774666647774).

The spelling of 14342315323433 in words is "fourteen trillion, three hundred forty-two billion, three hundred fifteen million, three hundred twenty-three thousand, four hundred thirty-three".

Divisors: 1 419 34229869507 14342315323433