143431042234121 has 4 divisors (see below), whose sum is σ = 143431079578752. Its totient is φ = 143431004889492.

The previous prime is 143431042234087. The next prime is 143431042234133. The reversal of 143431042234121 is 121432240134341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 143431042234121 - 2⁶ = 143431042234057 is a prime.

It is a super-3 number, since 3×143431042234121³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (143431042234171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12152321 + ... + 20845646.

It is an arithmetic number, because the mean of its divisors is an integer number (35857769894688).

Almost surely, 2^{143431042234121} is an apocalyptic number.

It is an amenable number.

143431042234121 is a deficient number, since it is larger than the sum of its proper divisors (37344631).

143431042234121 is an equidigital number, since it uses as much as digits as its factorization.

143431042234121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37344630.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 143431042234121 its reverse (121432240134341), we get a palindrome (264863282368462).

The spelling of 143431042234121 in words is "one hundred forty-three trillion, four hundred thirty-one billion, forty-two million, two hundred thirty-four thousand, one hundred twenty-one".